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[Issue Essay]

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题目:

Analytical!

选项:

答案:

提问:

早安麻烦老师帮我解答一下61题,我不懂这个解释。我的思路是:9个人两组,人数多那一组最多不能超过6个人,那么一共有两种分法 4 5和3 6 。然后结合题目要求人多的那一组必须包含固定的五个人 a b c e f , 如果是 4 5 分 多的那一组只能是这五个人 那分法是固定的。如果是 3 6 分 六人组里面固定五个人 剩下一个从剩下的四个人里选一个搭配是 C 41 ,所以一共有四种分法 。总共五种分法满足题目要求 所以我觉得这个概率应该是 5/210

解答:

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解答: ken@boost.org.cn

提问:

有24个brand,对每个brand的四个方面进行评估,这四个方面是ABCD,评估结果有四种,excellent,good,not good,bad,至少有几个brand的两个方面either excellent or good? (1)至少有10个brand的两个方面是excellent (2)至少有12个brand的三个方面是good

解答:

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解答: sysadmin老师

提问:

a/c是否小于1? (1) a/(c-1)小于1 (2) (a-1)/c小于1

解答:

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解答: sysadmin老师

提问:

切线与圆

解答:

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阅读247195
解答: sysadmin老师

提问:

PS:总共66个学生,有18个是business major,24个是新生,还有36个什么也不是,我忘了最后是问,仅仅是新生不是business major 的还是仅仅是business major不是新生的? 构筑答案:好像答案不是12 就是16.。。 解析: 18和24代表的韦恩图圈圈有重合,36代表的是自己单独的圈圈。 Total =66; 36个学生不在Business和Fresh 范畴里面,所以F+B=30; F 和B的共有学生=12, 是B不是F=6; 是F不是B=12。

解答:

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解答: sysadmin老师

提问:

PS:挺简单的,就是一个数轴吧-5到15都涂黑了,然后问哪个式子能代表? |x-5|<10 这个不等式怎么解来着?忘了。。。变号问题

解答:

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解答: sysadmin老师

提问:

PS:讲一个租赁汽车的公司每一次购买会购买5辆新车,每次卖掉会卖掉3辆旧车,今年新增了14辆车,把每次买和每次卖都算做一次交易,问今年最少做了几次交易?

解答:

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解答: sysadmin老师

提问:

If it took Carol 1/2 hour to cycle from his house to the library yesterday, was the distance that he cycled greater then 6 miles? ( 1mile=5,280feet) (1) The average speed at which Carlos cycled from his house to the library yesterday was greater than 16 feet per second. (2) The average speed at which Carlos cycled from his house to the library yesterday was less than 18 feet per second

解答:

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解答: sysadmin老师

提问:

Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man? A. 22 B. 35 C. 56 D. 70 E. 105

解答:

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解答: sysadmin老师

提问:

if x is positive, is x >3 1. (x-1)^2 >4 2. (x-2)^2 >9

解答:

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解答: sysadmin老师

提问:

if the average of the consecutive even integers a,b, and c is less than 13a, which of the following best describes the value of a? 答案: a is positive 为什么呢?

解答:

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阅读246180
解答: sysadmin老师

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