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[Issue Essay]

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题目:

Analytical!

选项:

答案:

提问:

Shoppers at Retailer R who purchased substitute items from other manufacturers on DayI paid a total amount that was approximately 78 of the total shoppers would have paid had each of them been able to purchase ProductXon Day 1. “was 和 would have paid ”都在一个从句里,怎末会有两个谓语动词?“had each of them been able to...”这部分是跟谁啊?看不懂

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解答: 徐小梅

提问:

题目:求143∧89(143的89次方)除以7的余数 问题:(1)如何利用同余的概念推出最后的结果的? (2) 如果可以不用同余概念,还有什么其他方法可以处理此类题型嘛?

解答:

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解答: sysadmin老师

提问:

题目:A Printer numbered consecutively the pages of a book, beginning with 1 on the first page. In numbering the pages, he printed a total of 189 digits. How many pages are there in the book? 问题:看了中文翻译并听了管老师的讲解,我都没弄明白这个题目的解题思路。的别是对“a total of 189 digits”的处理。

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解答: sysadmin老师

提问:

DS:已知半径为7,求ABR 的周长? 条件1:∠x=120 度 条件2:△ABR 的面积为(49/9) π 图片附件

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解答: sysadmin老师

提问:

题目:If n is a prime number greater than 3, what is the remainder when n的平方is divided by 12? 问题:当管老师解题时,他出了3个方程式,分别是: 1) n=3A+1, n的平方=9A(square)+6A+1 2) n=3A+2, n的平方=9A(square)+12A+4 3) n=2A+1, n的平方=4A(square)+4A+1 我不明白的点是:这3个方程式是怎么推到或者是一看到题目就这么设出来的?

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解答: sysadmin老师

提问:

有图。

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解答: sysadmin老师

提问:

PS:问49.987*9.879/0.253化简结果最接近哪一个? 选项a.b.c忘记了,d是1700,e是1800

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解答: sysadmin老师

提问:

数学书60页32题,有多少小于20的正整数等于3的正倍数与4的正倍数只和,答案说10个,我怎么查都是11个

解答:

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解答: sysadmin老师

提问:

PS:一个数是两位数,这个数大于11,个位数和十位数加起来的和是质数,问这样的 数有多少个?

解答:

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解答: sysadmin老师

提问:

57)If m is a positive odd integer between 2 and 30, then m is divisible by how many different positive prime numbers? 1)m is not divisible by 3. 2)m is not divisible by 5. 条件1 我理解的是 M 只能2到30之间,那么就有5,7,11,13,17,19,23,29,这么多个prime numbers. 条件2 我理解的是 M 可以是 3,7,9,11,13,17,19,21,23,27,29 这些,21可以被3和7除, 我判断条件1完全可以,条件2 我不太确定

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解答: sysadmin老师

提问:

62)if d is the positive integer and f is the product of the first 30 positive integers what is the value of d? (1) 10d is a factor of f. (2) d > 6 这个题目说d 是一个正整数,f 是30!阶乘,d的值多少, 这个题应该怎么推理?

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解答: sysadmin老师

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