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[Data Sufficiency]

试题详情

题目:

The first four digits of the six-digit initial password for a shopper’s card at a certain grocery store is the customer’s birthday in day-month digit form. For example, 15 August corresponds to 1508 and 5 March corresponds to 0503. The 5th digit of the initial password is the units digit of seven times the sum of the first and third digits, and the 6th digit of the initial password is the units digit of three times the sum of the second and fourth digits. What month, and what day of that month, was a customer born whose initial password ends in 16 ?
  1. The customer’s initial password begins with 21, and its fourth digit is 1.
  2. The sum of the first and third digits of the customer’s initial password is 3, and its second digit is 1.

选项:

A、Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B、Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C、BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D、EACH statement ALONE is sufficient.
E、Statements (1) and (2) TOGETHER are NOT sufficient.

答案:

A

提问:

May老师明星课,条件二由第二位和第四位和的三倍个位数为6以及第二位是1,可以推出第四位是1;第一和第三位的和为3,无法确定,但这题是实际问题,考虑月的十位数(第三位)只能为0或1,只有两种情况吧?

解答:

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解答: 徐小梅

提问:

May老师明星课,条件二由第二位和第四位和的三倍个位数为6以及第二位是1,可以推出第四位是1;第一和第三位的和为3,无法确定,但这题是实际问题,考虑月的十位数(第三位)只能为0或1,只有两种情况吧?

解答:

点赞0
阅读897
解答: 徐小梅老师

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