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[Problem Solving]

试题详情

题目:

A set of numbers has the property that for any number t in the set, t + 2 is in the set.  If –1 is in the set, which of the following must also be in the set?
 
I.    -3
II.    1
III.   5

选项:

A、I only
B、II only
C、I and II only
D、II and III only
E、I, II, and III

答案:

D

提问:

A set of numbers has the property that for any number t in the set, t+2 is in the set. If -1 is in the set, which of the following must be in the set? 1):-3 2):1 3):5 A:1 only B:2 only C:1&2 only D:2&3 only E:1,2,and 3 答案是D, 但我认为应该是E。答案只有2)&3)是因为一开始就假设t=-1,从-1开始推出+2=1,1+2=3,3+2=5。如果这样想:X+2=t,根据答案1必然在set中 则假设此时的t=1,倒退出x=-1。但为什么不能假设X+2=t(-1),得出X=-3?因为-1在set中,所以-1一定是另一个数+2后的结果,所以-1=-3+2, 故-3也在set中。 谢谢老师解答

解答:

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解答: sysadmin

提问:

我选的E 思路是 -3在set里 所以1在set里 所以1+2=3在set里 然后3+2=5在set里

解答:

点赞1
阅读1949
解答: 姜山老师

提问:

为什么-3不行呢~~

解答:

点赞4
阅读2000
解答: sysadmin老师

提问:

A set of numbers has the property that for any number t in the set, t+2 is in the set. If -1 is in the set, which of the following must be in the set? 1):-3 2):1 3):5 A:1 only B:2 only C:1&2 only D:2&3 only E:1,2,and 3 答案是D, 但我认为应该是E。答案只有2)&3)是因为一开始就假设t=-1,从-1开始推出+2=1,1+2=3,3+2=5。如果这样想:X+2=t,根据答案1必然在set中 则假设此时的t=1,倒退出x=-1。但为什么不能假设X+2=t(-1),得出X=-3?因为-1在set中,所以-1一定是另一个数+2后的结果,所以-1=-3+2, 故-3也在set中。 谢谢老师解答

解答:

点赞0
阅读1905
解答: sysadmin老师

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